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This solution works even when P is moved to the other side of g. This happens because the other intersection of the two circles is automatically kept away from the already known point P. |
| Here is the solution. |
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This solution works even when P is moved to the other side of g. This happens because the other intersection of the two circles is automatically kept away from the already known point P. |
You may move the different construction elements to see how the
construction works.